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A little monkey had 60 peaches.

On the first day he decided to keep 3/4 of his peaches.
He gave the rest away. Then he ate one.

On the second day he decided to keep 7/11 of his peaches.
He gave the rest away. Then he ate one.

On the third day he decided to keep 5/9 of his peaches.
He gave the rest away. Then he ate one.

On the fourth day he decided to keep 2/7 of his peaches.
He gave the rest away. Then he ate one.

On the fifth day he decided to keep 2/3 of his peaches.
He gave the rest away. Then he ate one.

How many did he have left at the end?

 

 

This one looks super complicated - but like most things with fractions, it isn't. I'll get you started off, all you have to do is carry on the investigation using the same method.

 

Our monkey has 60 peaches.

He keeps 3/4 of them - the rest he gives away. Then he eats one. 

So, we need to figure out what 3/4 of 60 is. Then take one away for the peach he scoffs.

 

What is 3/4 of 60? Well, that 4 at the bottom of 3/4 mean we have to divide 60 by 4. Division, fractions, same thing. 60/4 = 15 (that's the hardest of the division sums done for you - because 4 x 15 = 60!). 

But that's only one quarter! We've got 3 of them! So 15 x 3 =  45.

He chomps one, so 44.

 

Remember - to find a fraction of a number (any number!) you divide by the bottom number of the fraction first, then times that answer by the top number. So 7/11 of 99 would be 99 divided by 11 - which is 9. Then times 9 by 7, which is 63. Divide, then times, job done! Don't forget that the monkey eats one...

 

DANGER - CHALLENGE FOR SUPER BRAINBOXES ONLY:

A little monkey had 75 peaches.

Each day, he kept a fraction of his peaches, gave the rest away, and then ate one.
These are the fractions he decided to keep:

1/2

1/4

3/4

3/5

5/6

11/15

In which order did he use the fractions so that he was left with just one peach at the end?

 

 

 

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